Question

A transformer with a power efficiency of 80% converts a 10 V primary input voltage (with a current of 10 A) to a voltage of 20 V. The current in the secondary coil will be O 15 A O 4 A O ZA O 10 A​

Answer 1

Answer:

2) 4 A

Explanation:

Efficiency of transformer = I₂V₂ / I₁V₁

      80/100 = 20 x I₂ / 10 x 10

      = 4 A

Answer 2

Answer:

Current in secondary coil is 4 Ampere.

Explanation:

A device that converts electrical energy into mechanical energy is called transformer . The transmission current is alternating current (AC).

It's widely used to adjust the supply voltage between circuits without changing the frequency of the AC.It is based on the electromagnetic changing the frequency of the AC.It is based on the electromagneticinduction and mutual induction concepts.

efficiency of transformer is    

     η = $\frac{P_{out} }{P_{in} } \times 100$  

   $P_{out}$= output power  

    $P_{in}$= input power      

       η =  $\frac{V_{2} I_{2} }{V_{1} I_{1} }$

Given :                 V₁ = 10 v     V₂ = 20v    

                              I₁= 10A        η= 80%  

Putting vaules in formula  

 $80 = \frac{20\times I_{2} }{10\times 10} \times 100$  

 $80={20I_{2} }$    

 $I_{2}= 4 A$

Hence Current in Secondary coil is 4 Ampere .