Question

A transformer with an output voltage
of 4200V is supplied at 230v. If the
seconda
ary
has 2000 turns, calculate the
number of turns?​

Answer 1

Answer:

n1 =110

Explanation:

v1 = 230

v2 = 4200

n2=2000

n1=?

n1/n2=v1/v2

n1= (v1/v2)*n2

n1 = (230/4200)*2000

n1 =110

Answer 2

Answer:

The number of turns in the secondary coil of the transformer is approximately 109.52.

Explanation:

To calculate the number of turns in the primary coil of the transformer, we can use the formula:

$Vp/Vs = Np/Ns$

where Vp is the voltage in the primary coil, Vs is the voltage in the secondary coil, Np is the number of turns in the primary coil, and Ns is the number of turns in the secondary coil.

Given that the output voltage of the transformer is 4200V and the input voltage is 230V, we can substitute these values into the formula to get:

$230/Ns = 4200/2000$

Simplifying the right-hand side of the equation:

$230/Ns = 2.1$

Multiplying both sides of the equation by Ns:

$230 = 2.1*Ns$

Dividing both sides of the equation by 2.1:

$Ns = 230/2.1$

$Ns ≈ 109.52$

Therefore, the number of turns in the secondary coil of the transformer is approximately 109.52.

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