Question

A transformer without power loss has 1500 turns in primary coil and 7500 turns in secondary coil.secondary coil delivers 100 W power at 250V. calculate voltage across primary coil.​

Answer 1

Explanation:

this is ur prim voltage..

Answer 2

Answer:

A transformer without power loss has 1500 turns in the primary coil and 7500 turns in the secondary coil, the secondary coil delivers 100 W power at 250V, the voltage across the primary coil is 50v

​Explanation:

• In a transformer, there is a primary coil with a number of turns $N_{1}$ voltage, and current through it is $I_{1}$. In the secondary coil, the number of turns is $N_{2}$ voltage is $V_{2}$ and current is $I_{2}$

• The relation connecting these parameters is given by the formula

        $\frac{N_{1} }{N_{2} } =\frac{V_{1} }{V_{2} }=\frac{I_{2} }{I_{1} }$

From the question, we have

the number of turns in the primary coil $N_{1} =1500$

the number of turns in the secondary coil $N_{2} =7500$

the voltage in the secondary coil is $V_{2} =250v$

the voltage in the primary coil is $V_{1} =\frac{N_{1}*V_{2} }{N_{2} }$

⇒$V_{1} =\frac{1500*250}{7500}=50v$