Question

A transformer working on a 2 V AC supplies a voltage of 8 V to an electric bell in the circuit. The number of turns in the primary coil is 4800. Calculate the number of turns in the secondary coil​

Answer 1

★ Given Question :

• A transformer working on a 2V AC supplies a voltage of 8 V to an electric bell in the circuit. The number of turns in the primary coil is 4800. Calculate the number of turns in the secondary coil

★ Required Solution :

✯ Values Given to us :

• ➟ V1 = 2

• ➟ V2 = 8

• ➟ N1= 4800

✯ Formula Used Here :

• ➟ V2 / V1 = N2 / N1

★ Concept Behind :

• ⟶ To Find the number of turns in second coil at first we have to indicate a transformer working voltage as V¹ and AC working voltage as V² and Number of turns in the coil be N.

✯ Putting Values in Formula :

• ➟ 8 / 2 = N2 / 4800

• ➟ N2 = 4800 × 8 / 2

• ➟ N2 = 4800 × 4

• ➟ N2 = 19200

⚘ No. of Turn in Coil is 19200

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Answer 2

Explanation:

✫ Given Question :

The surface area of an object is 20 m² and a force of 10 N is applied on it, then what is the pressure?

✫ Required Solution :

✩ Values Given to us :

⟼ Surface area of an object is 20 m²

⟼ Force of 10 N is applied

✩ Formula Uses Here :

⟼ Pressure = Force / Area

✩ Concept Behind :

⟼ To Find pressure on object , we have to use a formula of Pressure by applying the formula of pressure we can easily calculate it

✫ Putting Values in Formula :

⟼ Pressure = 10 / 20 N /m²

⟼ Pressure = 0.5 N/m²

⟼ ⚘ Pressure = 0.5 N/m² ⚘

or

⟼ ⚘ Pressure = 0.5 Pascal ⚘

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