Question

A transformer working on a 240 V AC supplies a voltage of 8 V to
an electric bell in the circuit. The number of turns in the primary
coil is 4800. Calculate the number of turns in the secondary coil.​

Answer 1

ANSWER
========


There are two types of transformers

1). Step up transformer

2). Step down transformer


Coming to the question


First of all we need to write the given information

V1 = 240 v

V2= 8 v

N1 = 4800

N2 = ?

We need to find the value of N2 that means we need to calculate the value of the secondary coil

So applying the general formula

V2/v1 = N2/N1

For calculating N2 we need to arrange this formula


N2= v2 x N1 /v1


N2 = 8 x 4800 / 240


N2 = 38400/240

N2 = 160


So the number of turns in the secondary coil is 160

Answer 2

Explanation:

The number of turns in the secondary coil is 160.

Let us consider N2 ( The number of turns in the secondary coil) be x.

We have,

⚪V1 = 240 V

⚪V2 = 8 V

N1 (The number of turns in the primary coil) = 4800.

Using The Relation

$\dfrac{V2}{V1}$

= $\dfrac{N2}{N1}$

Putting given value in the relation,

$\dfrac{V2}{V1}$

= $\dfrac{N2}{N1}$

✏$\dfrac{240}{8}$

= $\dfrac{N2}{4800}$

✏N2 = $\dfrac{4800 × 8}{240}$

✏N2 = $\dfrac{4800 × 8}{240}$

✏N2 = $\cancel{\dfrac{38400}{240}}$

✏N2 = 160

(◕)The number of turns in the secondary coil is 160.

✿NOTE✿

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