A transformer working on a 240 V AC supplies a voltage of 8 V to an electric bell in the circuit. The number of turns in the primary coil is 4800. Calculate the number of turns in the secondary coil
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- A transformer is working on a 240 V AC supplies a voltage of 8 V to an electric bell in the circuit.
- The number of turns in first coil=4800
- The number of turns in second coil=?
- To calculate the number of turns in second coil at first we have to indicate a transformer working voltage as V¹ and AC working voltage as V² and Number of turns in the coil be N. After that simply by applying formula to calculate the number of turns in the second coil. Simplify it by proportionally.
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- A transformer working on a 240 V AC supplies a voltage of 8 V to an electric bell in the circuit.
- The number of turns in the primary coil is 4800.
- The number of turns in the secondary coil.
Let us consider N2 ( The number of turns in the secondary coil) be x
We have,
V1 = 240 V
V2 = 8 V
N1 (The number of turns in the primary coil) = 4800.
Using The Relation ,
=
Putting given value in the relation,
★ =
➝ =
➝ N2 = × 4800
➝ N2 =
➝ N2 =
➝ N2 = 160
✒ The number of turns in the secondary coil is 160.
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