A transformer working on a 240 V AC supplies a voltage of 8 V to an electric bell in the circuit. The number of turns in the primary coil is 4800. Calculate the number of turns in the secondary coil
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★ Given Question :
- A transformer working on a 240 V AC supplies a voltage of 8 V to an electric bell in the circuit. The number of turns in the primary coil is 4800. Calculate the number of turns in the secondary coil
★ Required Solution :
✯ Values Given to us :
- ⟶ V1 = 240
- ⟶ V2 = 8
- ⟶ N1= 4800
✯ Formula Used Here :
- ⟶ V2 / V1 = N2 / N1
★ Concept Behind :
- ⟶ To Find the number of turns in second coil at first we have to indicate a transformer working voltage as V¹ and AC working voltage as V² and Number of turns in the coil be N.
✯ Putting Values in Formula :
- ⟶ 8 / 240 = N2 / 4800
- ⟶ N2 = 4800 × 8 / 240
- ⟶ N2 = 20 × 8
- ⟶ N2 = 160
⚘ No. of Turn in Coil is 160
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