Question

A transformer working on a 240 V AC supplies a voltage of 8 V to an electric bell in the circuit. The number of turns in the primary coil is 4800. Calculate the number of turns in the secondary coil​

Answer 1

★ Given Question :

• A transformer working on a 240 V AC supplies a voltage of 8 V to an electric bell in the circuit. The number of turns in the primary coil is 4800. Calculate the number of turns in the secondary coil

★ Required Solution :

✯ Values Given to us :

• ⟶ V1 = 240

• ⟶ V2 = 8

• ⟶ N1= 4800

✯ Formula Used Here :

• ⟶ V2 / V1 = N2 / N1

★ Concept Behind :

• ⟶ To Find the number of turns in second coil at first we have to indicate a transformer working voltage as V¹ and AC working voltage as V² and Number of turns in the coil be N.

✯ Putting Values in Formula :

• ⟶ 8 / 240 = N2 / 4800

• ⟶ N2 = 4800 × 8 / 240

• ⟶ N2 = 20 × 8

• ⟶ N2 = 160

⚘ No. of Turn in Coil is 160

________________________