Question

A transformer working on a 30 V AC supplies a voltage of 8 V to an electric bell in the circuit. The number of turns in the primary coil is 4800. Calculate the number of turns in the secondary coil ?​

Answer 1

★ Given Question :

• A transformer working on a 30 V AC supplies a voltage of 8 V to an electric bell in the circuit. The number of turns in the primary coil is 4800. Calculate the number of turns in the secondary coil

★ Required Solution :

✯ Values Given to us :

• ⟶ V1 = 30 v

• ⟶ V2 = 8 v

• ⟶ N1= 4800

✯ Formula Used Here :

• ⟶ V2 / V1 = N2 / N1

★ Concept Behind :

• ⟶ To Find the number of turns in second coil at first we have to indicate a transformer working voltage as V¹ and AC working voltage as V² and Number of turns in the coil be N.

✯ Putting Values in Formula :

• ⟶ 8 / 30 = N2 / 4800

• ⟶ N2 = 4800 × 8 / 30

• ⟶ N2 = 4800 × 4 / 15

• ⟶ N2 = 1,280

• No. of Turn in Coil is 1,280

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