Question

A transistor has an IC of 100 mA
and IB of o.5mA. What is the value
of adc
@ 0.565 60 754 © 1.24 & 0.995​

Answer 1

Step-by-step explanation:

Given A transistor has an IC of 100 mA and IB of 0.5 mA. What is the value of adc

• Given In a transistor the collector current Ic = 100 mA
• Base current Ib = 0.5 mA
• We need to find the value of adc.
• So we have
• Emitter current Ie = Ib + Ic
•                            = 0.5 + 100
•                            = 100.5 mA
• So adc = Ic / Ie
•            = 100 / 100.5
•            = 0.995
• Therefore the value of adc will be 0.995

Reference link will be

https://brainly.in/question/20020150