A translucent white waxy solid (A) on heating in an inert atmosphere is converted into its allotropic form (B). Allotrope (A) on reaction with very dilute aqueous KOH liberates a highly poisonous gas (C) having rotten fish smell. With excess of chlorine (C) forms (D) which hydrolyses to compound (E). Identify (A) to (E)
CBSE 1999 Class 12th
Answers
Hey !!
(i) Since a translucent white waxy solid (A), on heating in an inert atmosphere, is converted into its allotrope (B), therefore, (A) is white or yellow phosphorous while (B) is red phosphorous.
P₄ (s) ----->(Heat, inert gas) P₄ (s)
(White phosphorous) (Red phosphorous)
(ii) Since allotrope (A) on boiling with dilute aqueous KOH gives a highly poisonous gas (C) having rotten fish smell, therefore, it is confirmed that ''allotrope'' is white phosphorous gas (C) is phosphine (PH₃)
P₄ (s) + 3 KOH (aq) + 3 H₂O (l) --(Heat)--> 3 KH₂PO₂ + PH₃
(White phosphorus) (Pot. hypophosphite) (Phosphine) (C)
(iii) Since phosphine (C) reacts with excess of chlorine to form a compound (D) which upon hydrolysis gives compound (E), therefore, (D) must be phosphorous (PCl₅) and (E) must be phosphoric acid (H₃PO₄)
PH₃ (g) + 4 Cl₂ (g) ------> PCl₅ + 3 HCl (g)
Phosphine (C) (Excess) (Phosphorous pentachloride) (D)
PCl₅ (s) + 4 H₂O (l) -----> H₃PO₄ (aq) + 5 HCl
(D) (Phosphoric acid) (E)
Thus, (A) is white phosphorus (B) is red phosphorous (C) is phosphine (PH₃). (D) is phosphorus pentachloride and (E) is phosphoric acid (H₃PO₄)
GOOD LUCK !!
Hello! Dear User!
Answer!
>>>>Translucent waxy solid is actually white phosphorus (P4)
>>>>P4 on heating gives red phosphorus in inert atmosphere
>>>>P4 on reaction with KOH gives phosphine , a poisonous gas
>>>> P4 + KOH + H2O ⇒ PH3 + KH2PO2
>>>>Now P4 on excess of chlorine gives PCl5 which on hydrolysis gives POCl3 and H3PO4
>>>>>P4 + 10Cl2 ⇒ 4PCl5
>>>>>PCl5 + H2O ⇒ POCl3 + 2HCl
>>>>POCl3 + 3H2O ⇒ H3PO4 + 3HCl
A : (white phosphorus)
B : (red )phosphorous
C : (Phosphine (PH₃)
D : (Phosphorus pentachloride)
E : (Phosphoric acid (H₃PO₄)
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