A transmitter of 10kw is emitting radio waves of wavelength 500nm . How many photons per second are emitted by the transmitter
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Answer:
Energy emitted by the transmitter per sec,Et = 10kW
Energy of the wave, Ew = hc/λ
where λ= 500m
Plugging the values gives Ew = 3.96 * 10-28
No of photons emitted per sec, n = Et / Ew = 10000 / 3.96 * 10-28 = 2.5 * 1031
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