Question

a transparent glass plate of thickness 0.5mm and refractive index 1.5 is placed infront of one of the slits is in a double slit experiment if the wavelength of light used is 6000A° the ratio of maximum to minimum intensity in the interference pattern is 25/4 then the ratio of light intensity transmitted to incident on thin transparent glass plate is​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

9/49

Explanation:

Given, Imax/Imin = 25/4

25/4 = (A1 + A2)^2 / (A1 - A2)^2

(A1 + A2) / (A1 - A2) = 5/2

2A1 + 2A2 = 5A1 - 5A2

5A1 - 2A1 = 5A2 + 2A2

3A1 = 7A2

A1 / A2 = 7/3

But A directly proportional to √I

Therefore, A1 / A2 = √( I1 / I2)

I1 / I2 = (7/3)^2

I1 / I2 = 49/9

I2 / I1 = 9/49

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