Question

A transparent glass plate of thikness 0.5 mm and refrecative index 1.5 is placed infront of one of the slits in a double slit expremint. If the wavelength of light used is 6000 a 0 ,the ratio of maximum to minimum intensity in the interference pattern is 25/4. Then the ratio of light intensity transm

Answer 1

Answer:

F

Explanation:

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fougu

Answer 2

Ratio = 4: 5

Explanation:

(μ - 1) t = xd/ D

μ = 1 + xd/Dt

μ = 1 + (0.5 * 0.2) / (10 * 0.05)

    = 1 + 1.0/0.5

    = 1 + 0.2

μ   = 1.2

Ratio = 1.2 : 1.5 = 4: 5