Physics, asked by Anonymous, 8 months ago

A transparent sphere of radius R and
refractive index n is kept in air. At what distance
from the surface of the sphere should a point
object be placed on the principal axis so as to
form a real image at the same distance from the
second surface of the sphere?​

Answers

Answered by as3451574
2

Answer:

Given: A transparent sphere of radius R and refractive index μ is kept in the air.

To find the distance from the surface of the sphere where a point should be placed so as to form a real image at the same distance from the other side of the sphere

Solution:

Using the equation,

v

μ

2

u

μ

1

=

R

μ

2

−μ

1

For the refraction at the first surface of the sphere,

(air to glass)

μ

−x

1

=

R

μ−1

, Here x is the distance of point object from the sphere, as shown in above fig.

x

1

=

R

μ−1

⟹x=

μ−1

R

Hence the object should be placed this distance from the surface of the sphere in order to get real image.

solution

Explanation:

HOPE ITS HELPFUL

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