Question

a transversal cut two Parallel Lines at a and b the two interior angle at a bisected and so are two interior angle at b the four bisectors from a quadrilateral ACBD prove that. 1= ACBD is a triangle. 2= CD is parallel to original parallel lines​

Answer 1

Answer:

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Answer 2

Answer:

To prove → ABCD is a rectangle

AD, CD, AB, BC are bisectors of interior angles formed by transversal line with ∥ line.

∠BCA=∠CAB

Hence,CB∥AB

Similarly,AB∥CB(∠CAB=∠ACB) (Alternateangles)

Therefore quadrilateral ABCD is a ∥gram as both the pairs of opposite sides are ∥

∠b+∠b+∠a+∠a=180

⇒2(∠b+∠a)=180

∠a+∠b=90

That is ABCD is ∥gram & one of the angle is ⊥ angle.

So, ABCD is a Rectangle.

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