a transversal ef of line ab and line cd intersects thr lines at point p and q respectively ray pr and ray qs are parallel and bisectors of angle bpq and angle pqc respectively prove that line ab parallel to line cd
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line ab and line cd are parallel by corrwsponding angles
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Answer:
line ab || line cd
Step-by-step explanation:
let angle BPR = angle QPR = x ( ray PR bisects BPQ) [1]
angle CQS = angle PQS = y ( ray QS bisects PQC) [2]
∴angle BPQ = angle BPR + angle QPR (angle addition)
∴angle BPQ = x + x (from 1)
∴angle BPQ = 2x [3]
∴angle PQC = angle PQS + angle CQS (angle addition)
∴angle PQC = y + y (from 2)
∴angle PQC = 2y [4]
ray PR || Ray QS ( || means 'is parallel to')
∴on transversal PQ
∴angle QPR = angle PQS (alt. angles theorem)
∴ x = y (from 1 and 2)
∴ 2x = 2y (multiplying both by 2)
∴angle BPQ = angle PQC (from 3 and 4)
∴ line AB || line CD (by alt. angles test)
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