Math, asked by arpitmittal1221, 4 months ago

a transversal intersects a pair of parallel lines ab and cd at p and q respectively. if the bisectors pm and qm of the angles apq and cqp meet at m what is angle pmq
PLEASE GIVE EXPLANATION IN DETAIL

Answers

Answered by Anonymous
4

Step-by-step explanation:

The transversal AD intersects the two lines PQ and RS at points B and C respectively. BE is the bisector of ∠ABQ and CF is the bisector of ∠BCS.

As, BE is the bisector of ∠ABQ, then,

∠ABE=

2

1

∠ABQ

In the same way,

∠BCF=

2

1

∠BCS

Since BE and CF are parallel and AD is the transversal, therefore, by corresponding angle axiom,

∠ABE=∠BCF

2

1

∠ABQ=

2

1

∠BCS

∠ABQ=∠BCS

Therefore, by the converse of corresponding angle axiom,

PQ∥RS.

Answered by panashyadav
1

It will be verified by theorem 11.1 .

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