Question

a transversal intersects two parallel lines then prove that bisectors of any pair of corresponding angles so formed are parallel.
plzz tell me the ans for this question

Answer 1

let the corresponding angle c and G measure 60 degree
the sum of C+E(it is the next angle to C) =180
as
C=60
while E+G=180(linear pair)
G=60(as both C and G is corresponding )
=60+E=180
E=120
thus C+E=180
60+120=180 and they are parallel

at last we can conclude that if the line of two angle are parallel the the sum of their interior angle will be 180

now ,
if corresponding angles are bisected
1.C/2=60/2=30
2.if G is bisected ,then the angle next to the 30 degtee (bisected c) will be the sum of E and G/2 such as in the pair C and E
3.now,lets see the sum of angle
=c/2+e+g/2
=30+120+30
=180

thus the bisector will be parallel as the sum of their interior angle is 180

Answer 2

hence it is proved that parallel