a transversal line intersect two Parallel Lines then prove that bisector of any pair of corresponding angle so formed are parallel
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ABis parallel to CD & transversal EF intersct them at G and H respectively.
therefore ,angleEGB=angleGHD
1/2angleEGB= 1/2 angle GHD
angleEGM=angleGHN
thus,lines GM&HN are intersected by a transversal GH at G & H respectively .
therefore , the coreesponding angles are equal.
hence, GM||HN.
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