A transversal XY cuts two lines PQ and RS at distinct points to
form angles 1 to 8. angle7 is thrice angle6 and angle1 is the sum of twice angle2
and 45°. If PQ and RS are parallel, find all the angles
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let assume angle 6 is x. so, angle 7 will be 3x.
x+3x= 180
x=45
now, angle 6 is 45° and angle 7 is 45×3=135°
and by seeing all the relation between the angles
1=135
2=45
3=135
4=45
5=135
6 and 8 = 45
and 7= 135
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