A transverse sinusoidal wave moves along a string in the positive direction in x-axis at a speed of 10 cm/so. The wavelength of the wave is 0.5 cm and it's amplitude is 10 cm. At a particular time t, the snap-shot of the wave is shown in figure. The velocity at point P when it's displacement is 5 cm is?
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The particle velocity Vp is related to the displacement of the particle from its mean position.
Vp = omega under root A^2 - y^2
= 2 pie v under root A^2 - y^2
= 2 pie (v/lambda or wavelength) under root A^2 - y^2
= 2 pie/0.5 × 0.1 under root (0.1)^2 - (0.05)^2
= under root 3 pie/50 j^ m/s
Is the final answer.
Since the wave is travelling in the positive direction, the particle P must have its velocity in positive Y direction at the moment of the given time.
Vp = omega under root A^2 - y^2
= 2 pie v under root A^2 - y^2
= 2 pie (v/lambda or wavelength) under root A^2 - y^2
= 2 pie/0.5 × 0.1 under root (0.1)^2 - (0.05)^2
= under root 3 pie/50 j^ m/s
Is the final answer.
Since the wave is travelling in the positive direction, the particle P must have its velocity in positive Y direction at the moment of the given time.
Answered by
8
Answer:
Explanation:The particle velocity Vp is related to the displacement of the particle from its mean position.
Vp = omega under root A^2 - y^2
= 2 pie v under root A^2 - y^2
= 2 pie (v/lambda or wavelength) under root A^2 - y^2
= 2 pie/0.5 × 0.1 under root (0.1)^2 - (0.05)^2
= under root 3 pie/50 j^ m/s
Is the final answer.
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