Question

A transverse wave described by
y=(0·02 m) sin (1·0 m-1) x+(30 s-1)t
propagates on a stretched string having a linear mass density of 1·2×10-4 kg m-1. Find

Answer 1

Tension is 0.108 N

Explanation:

Let T= tension  

Linear mass density (m) = $1.2\times 10^-^4\ kgm^-^1$

we know wave speed = $\frac {w}{k}= 30/1=30\ ms^-^1$

implies that  

we know v = $\sqrt (\frac {T}{m})$

implies that

30 = $\sqrt (\frac {T}{m})$

=> $900\times 1.2 \times 10^-^4$ = T

=> T = 0.108 N