Question

a Trapezium PB QC with its parallel side QC and PB in the ratio 7 ratio 5 is cut off from a rectangle ABCD if the area of the trapezium is 4 upon 7 part of the area of the rectangle find the length of QC and PB ​

Answer 1

Answer:

Step-by-step explanation:

Let QC = 7x cm and PB = 5x cm

Area (Trapezium PBCQ) =× Area (Rectangle ABCD)

⇒× 5 × (7x + 5x) =× 5 × 21

⇒ 30x = 60

⇒ x = 2

Thus, QC = 14 cm and PB = 10 cm.