Question

A trapezium PBCQ with its parallel sides QC and PB in the ratio 7:5 is cut from a
rectangle ABCD, if area of trapezium is part of the area of rectangle, find the length of QC and PB.

Answer 1

Answer:

Step-by-step explanation:

Given  

A trapezium PBCQ with its parallel sides QC and PB in the ratio 7:5 is cut from a  rectangle ABCD, if area of trapezium is 4/7  part of the area of rectangle, find the length of QC and PB.

Given we know that area of rectangle = l x b = 5 x 21 = 105 sq cm

Area of trapezium will be = 4/7 of area of rectangle = 4/7 x 105 = 60 sq cm

Let QC = 7 a and PB = 5 a

Now Area of trapezium = ½ x sum of parallel sides x altitude

60 = 1/2 x 12 a x 5

120 = 60 a

 a = 2

QC = 7 a = 7 x 2 = 14 cm

PB = 5 a = 5 x 2 = 10 cm