A trapezium PQRS is such that PQ || RS and the perpendicular from P to RS is 40 cm. If | PQ = 20 cm, |SP= 50 cm and SRI = 60 cm, calculate, correct to 2 significant figures, the area of the trapezium.
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Answer:
(a) Area of trapezium PQRS = 12(PQ+RS)×40
= 12(20+60)×40
= 40×40
= 1600cm2
(b) In Δ SPT,
|SP|2=|ST|2+|TP|2 (Pythagoras theorem)
|ST|2=|SP|2−|TP|2
= 502−402
= 2500−1600
|ST|2=900
∴|ST|=30cm
|UR|=60cm−(30+20)cm
= 10 cm
Let < QRS = α,
tanα=4010=4
α=tan−1(4)
= 75.96°≊76°
Answered by
1
Answer:
Area of trapezium PQRS = 12(PQ+RS)×40
= 12(20+60)×40
= 40×40
= 1600cm2
(b) In Δ SPT,
|SP|2=|ST|2+|TP|2 (Pythagoras theorem)
|ST|2=|SP|2−|TP|2
= 502−402
= 2500−1600
|ST|2=900
∴|ST|=30cm
|UR|=60cm−(30+20)cm
= 10 cm
Let < QRS = α,
tanα=4010=4
α=tan−1(4)
= 75.96°≊76°
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