Question

a trapezium shaped field whose parallel sides are 42m and 30m and other sides are 18m and18m find its area

Answer 1

refer the attachment

Answer 2

Answer: 432√2 m²

Step-by-step explanation:

Draw BE || AD, and we get ||gm ADEB and ΔBCE.

Area of ΔBCE = √[s(s - a)(s - b)(s - c)]

Where, s = ( a + b + c )/2

Here, s = [ 18 + 18 + ( 42 - 30 )] / 2

s = ( 18 + 18 + 12 ) / 2

s = 24 m

Area = √[ 24(24 - 18)(24 - 18)(24 - 12)]

= √( 2 × 12 × 6 × 6 × 12 )

= 12 × 6 √2

= 72√3

Area = 1/2 × base × height

72√2 = 1/2× 12 × h

72√2 × 2/12 = h

12√2 = Height of paralleogram and triangle

Area of trapezium = 1/2( a + b )h

Area = 1/2( 42 + 30 ) × 12√2

Area = 432√2 m²