Question

A trapezium with its parallel sides in the ratio
11 : 3 is cut off from a rectangle whose sides
measure 98 cm and 12 cm. The area of the
trapezium is of the area of the rectangle. Find
the lengths of the parallel sides of the trapezium,
when its height is equal to the smaller side of the
rectangle.​

Answer 1

that solve

this is right

Answer 2

The length of parallel sides are 154 cm and 42 cm.

Step-by-step explanation:

Since we have given that

Length of rectangle = 98 cm

Width of rectangle = 12 cm

Let the parallel sides of trapezium be 11x and 3x

Height of trapezium = smaller side of the rectangle = 12 cm

And Area of rectangle = Area of trapezium

$l\times b=\dfrac{1}{2}\times (a+b)\times h\\\\98\times 12=\dfrac{1}{2}\times (11x+3x)\times 12\\\\98=\dfrac{1}{2}\times 14x\\\\98=7x\\\\\dfrac{98}{7}=x\\\\14=x$

Hence, the length of the parallel sides are

$11x=11\times 14=154\ cm\\\\3x=3\times 14=42\ cm$

# learn more:

The area of a trapezium is 210 cm and its height is 12 cm. If the lengths of the parallel sides

are in the ratio 4:3, find the lengths of the parallel sides.​

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