A trapeziun with the parallel sides in the ratio 11:3 is cut off from a rectangle whose sides measure 98cm and 12 cm .the area of the trapiziun is 3/7of the area of the rectangle.find the lengths of the parallel sides of the trapizium
Answers
Answered by
3
Step-by-step explanation:
A trapezium PBCQ with its parallel sides QC and PB in the ratio of 7:5 is cut off from a rectangle ABCD if the area of trapezium is4/7 part of area of rectangle find the length of QC and PB
Area of Rectangle = AB * BC
Area of Trapezium = (1/2) ( PB + QC) * BC
Let say QC = 7x then PB = 5x
=> Area of Trapezium = (1/2)(5x + 7x) * BC
=> Area of Trapezium = 6x * BC
Area of Trapezium = (4/7) Area of Rectangle
=> 6x * BC = (4/7) * AB * BC
=> x = 2AB/21
QC = 7x = 2AB/3
PB = 5x = 10AB/21
if we say AB = 21 cm as per attached fig
then QC = 14cm & PB =
Similar questions