A trapezoidal notch has a base width of 0.75 m and a side slope of
1 horizontal : 2 vertical. Calculate the discharge over the notch for a head of
0.50 m by assuming C = 0.63.
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Step-by-step explanation:
Given A trapezoidal notch has a base width of 0.75 m and a side slope of 1.horizontal : 2 vertical. Calculate the discharge over the notch for a head of 0.50 m by assuming C = 0.63.
- So we have m = 0.50
- So tan theta = 0.50
- So for a head the discharge Q = 2/3 Cd √2g H1^3/2 (L + 4/5 H1 tan theta)
- = 2/3 x 0.63 x √2 g x (0.50)^3/2 (0.75 + (4/5 x 0.5 x 0.5)
- = 0.66 x 0.63 x √19.6 x 0.3535 (0.75 + 0.2)
- = 0.65073 x 0.95
- = 0.618 m^3/s
- So the discharge over the notch will be 0.618 m^3/s
Reference link will be
https://brainly.in/question/14999815
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