Math, asked by pertinjohn, 1 month ago

A trapezoidal notch has a base width of 0.75 m and a side slope of
1 horizontal : 2 vertical. Calculate the discharge over the notch for a head of
0.50 m by assuming C = 0.63.​

Answers

Answered by knjroopa
2

Step-by-step explanation:

Given A trapezoidal notch has a base width of 0.75 m and a side slope of 1.horizontal : 2 vertical. Calculate the discharge over the notch for a head of  0.50 m by assuming C = 0.63.

  • So we have m = 0.50
  • So tan theta = 0.50
  • So for a head the discharge Q = 2/3 Cd √2g H1^3/2 (L + 4/5 H1 tan theta)
  •                                                      = 2/3 x 0.63 x √2 g x (0.50)^3/2 (0.75 + (4/5 x 0.5 x 0.5)
  •                                                       = 0.66 x 0.63 x √19.6 x 0.3535 (0.75 + 0.2)
  •                                                                        = 0.65073 x 0.95
  •                                                                        = 0.618 m^3/s
  • So the discharge over the notch will be 0.618 m^3/s

Reference link will be

https://brainly.in/question/14999815

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