A Trauets with a speed of 12m/s to his office
and returns back with a speed of 18 m/s what
is his average speed ?
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Step-by-step explanation:
speed =distance/time
distance =speed x time
let the distance =d
let time taken to his office =t1 s
d = t1×12
t1= d/12
let time taken to return back, t2
t2 = d/18
total time taken = t1+t2
=d/12+d/18 =d(1/12 +1/18)= d(2+3/36)=5d/36
total distance = 2d
average speed = 2d / (t1+t2) = 2d ÷ 5d /36=2d×36/5d
= 2×36/5=14.4 m/s
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