Question

A travelling at4m/s has to stop for a woman at the next bus stop.this driver brakes but the bus continues to travel for 10m before stopping. Determine the bug's acceleration

Answer 1

Answer:

−2m/s

2

In the given question

u=20m/s

v=0m/s

t=10s

and a=?

we know the formula v =u + at

so putting the values we get

0 = 20 + a X 10

- 20 = 10 a

-2 = a

we get acceleration is -2 so retardation will be +2 m/ sec sq.

Answer 2

Answer:

u=4

v=0

s=10

v^2=u^2+2as where a is acceleration

0=4^2+2a×10

20a=-16

a=-16/20=-4/5

minus sign shows that it is retardation