Question

A travelling telescope is focused at the bottom a tank over a coin. Now tank is filled upto a height of 25 cm with a liquid of refractive index 1.6, by what distance the telescope be moved to focus on the coin again? ...​

Answer 1

Answer:

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Answer 2

The distance the telescope be moved to focus on the coin again is 15.6 cm.

Explanation:

Given that,

Height = 25 cm

Refractive index = 1.6

We need to calculate the distance the telescope be moved to focus on the coin again

Using formula of refractive index

$\mu=\dfrac{d_{re}}{d_{app}}$

$d_{app}=\dfrac{d_{re}}{\mu}$

Where, $d_{re}$ = real height

$d_{app}$ = apparent height

$\mu$ = refractive index

Put the value into the formula

$d_{app}=\dfrac{25}{1.6}$

$d_{app}= 15.6\ cm$

Hence, The distance the telescope be moved to focus on the coin again is 15.6 cm.

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Topic : refractive index

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