a travels some distance with a speed of 30km/h and returns with speed of 45km/h calculate the average speed of the train
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Hey
Here is your answer,
let d/2 be the distance covered by train with a speed of 30kmph in t1 hours
→t1=d/60
it covers d/2 distance with a speed of 45km/h in t2 hours
→t2=d/90
average speed = total distance/total time
=d/(t1+t2)
=1/(1/60+1/90)
=1/(3+2)/180
=180/5=36kmph
Hope it helps you!
Here is your answer,
let d/2 be the distance covered by train with a speed of 30kmph in t1 hours
→t1=d/60
it covers d/2 distance with a speed of 45km/h in t2 hours
→t2=d/90
average speed = total distance/total time
=d/(t1+t2)
=1/(1/60+1/90)
=1/(3+2)/180
=180/5=36kmph
Hope it helps you!
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