Science, asked by ahsanlm10, 3 months ago

A tray for making ice-cubes is filled with 0.5 kg liquid water at 15°C. It is now put into the freezer where it is cooled down to -10°C using 50 W of electrical power input. The freezer sits in a room at 25°C having a coefficient of performance equal to 30% of maximum possible. How much
energy is used as work input to accomplish this process? If we neglect other cooling loads how much time will this process take? Take Cp of water = 4.18 kJ/kg K, Cp of ice = 2.1 kJ/kgk and latent heat of ice = 333.3 kJ/kg​

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Answered by ashwanidby29
0

Answer:

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Explanation:

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