Question

A tree, 10 feet tall , stands in front of an 18-feet-high building. If the tree is 15 feet away from the building, find the distance between their tops.

Answer 1

Answer: distance = Sin⁻¹(tan⁻¹(8/15)) * 8 ft   or Cos⁻¹(tan⁻¹(15/8)*15 ft

Step-by-step explanation:

p=8 ft      (height of building - height of tree)

b= 15 ft     (distance between them from foot)

h= ?        (distance between the top of them)

now

tan@=p/b

tan@=8/15

@=tan⁻¹(8/15)

∵ @= 1.6937570288

now,

sin@= p/h

sin(1.6937570288) = 8/h

h=sin⁻¹(1.6937570288)*8