A tree 12 m high is broken by the wind in such a way that its top touches the ground and makes an angle of 60° with the ground at what height from the bottom the tree is broken by the wind
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Let the height from the bottom where the tree is broken be ‘h’ m
Hence AC = (12 – h) m
In right triangle ABC
sin 60° = (AB)/(AC)
(√3/2 )= h/(12 – h)
12√3 – √3h = 2h
√3h + 2h = 12√3
h(√3 + 2) = 12√3
Therefore, h = 12√3/ (√3 + 2) m
Let the height from the bottom where the tree is broken be ‘h’ m
Hence AC = (12 – h) m
In right triangle ABC
sin 60° = (AB)/(AC)
(√3/2 )= h/(12 – h)
12√3 – √3h = 2h
√3h + 2h = 12√3
h(√3 + 2) = 12√3
Therefore, h = 12√3/ (√3 + 2) m
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