A tree 12m high is broken by the wind in such a way that its top touches the ground and makes an angle of 60o with the ground. At what height from bottom the tree is broken by the wind. Give the answer to the second place of decimal.
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Answer:
h = 12√3/ (√3 + 2) m
Step-by-step explanation:
Let the height from the bottom where the tree is broken be ‘h’ m
Hence AC = (12 – h) m
In right triangle ABC
sin 60° = (AB)/(AC)
(√3/2 )= h/(12 – h)
12√3 – √3h = 2h
√3h + 2h = 12√3
h(√3 + 2) = 12√3
Therefore, h = 12√3/ (√3 + 2) m
hope it helps you
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pradeep3532:
thank you
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