Question

A tree 32 m high broke at a point 7 m above the ground but did not separate. Its
top touched the ground. At what distance is the top of the tree from its bottom?

Answer 1

Step-by-step explanation:

25m

because a tree 32 m high broke at a point 7m above the ground but didn't seperate so 25 m

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Answer 2

Note : Refer to the attachment for figure

As per given in the Question ,

We have the following points ,

• Length of tree was 32 m
• If it broke at a point of 7 m then ,
• the length of broken tree would be 25 m ( 32 - 7 = 25 m )

So by applying Pythagoras theorem we will get the length of base ,

$\mapsto\:(AC)^2\:=\: (CB)^2\: + \:(BA)^2$

$\mapsto\:(25)^2\: = \:7^2\:+\: (BA)^2$

$\mapsto\:625 \:= \:49 \:+\: (BA)^2$

$\mapsto\:625\: - \:49\: =\: (BA)^2$

$\mapsto\:576\: =\: (BA)^2$

$BA$ = $\sqrt{576}$

$\mapsto\:BA\: = \:24\: m$

Hence , the distance from the top of the tree from its bottom is 24 m .

What is Pythagoras theorem ?

The Pythagoras theorem states that the square of Hypotenuse of a triangle will be equal to the sum of square of bothe the other sides .