Question

A tree 32 m high broke at a point 7 m above the ground but did not separate. Its
top touched the ground. At what distance is the top of the tree from its bottom?​

Answer 1

Answer:

We will solve it using Pythagoras theorem.

${ac}^{2} = {ab}^{2} + {bc}^{2} \\ \\ {(25)}^{2} = {7}^{2} + {bc}^{2} \\ \\ 625 = 49 + {bc}^{2} \\ \\ {bc}^{2} = 625 - 49 = 576 \\ \\ {bc}^{2} = 576 \\ \\ bc = \sqrt{572} \\ \\ = \sqrt{24 \times 24} \\ \\ bc = 24m$

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