A tree breaks due to storm and the broken part bends so that the top of the tree touches the ground making an angle 30 ° with it. The distance between the foot of the tree to the point where the top touches the ground is 10m. Find the height of the tree.
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let be the the height of tree is A'C=AC+BC
<B=90°
In ∆ABC,
tan30°=BC/10
BC=10/√3 . . . . . . (1)
again,
cos 30°=10/AC
AC=20/√3 . . . . (2)
A'C =(20/√3) +(10/√3)
=10√3 m
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