A tree breaks due to storm and the broken part bends so that the top of the
tree touches the ground where it makes an angle 45°. The distance between
the foot of the tree to the point where the top touches the ground is 10m.
Find the height of the tree from where it is broken.
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Answer:
let's take a right angle triangle ABC where angle C makes 45°
tan 45° = perp/base
1 = AB/BC
1 = AB/10
10=AB
again ,
sin 45° = perp/hypo
1/√2 = AB/AC
AC = 10√2
total height = AB + AC
= 10 + 10√2
10(1+√2)m
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