A tree broke at a point but did not separate Is top touched the ground at a distance of 5 m from its base.If the point where it broke is at a height of 12 m from the ground.What was the total height of the treebefore it broke?
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Thethe tree forms an angle of 90 degree and the length of the tree is 12m and the hypotenuse is when added to it becomes the total height of the tree the distance between the base of the tree and the point where is touch is 5m to according to pythagorus theorem .
P . sq + b . sq= h .sq
12×12 +5×5= h.sq.
144+25 = h.sq
h = root over of 169 =13m
Total height of tree is 12 +13=25m
P . sq + b . sq= h .sq
12×12 +5×5= h.sq.
144+25 = h.sq
h = root over of 169 =13m
Total height of tree is 12 +13=25m
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