Question

A tree broke at a point but did not separate. its top touched the ground at a distance of 24m from its base if the point where it broke be at a height of 7m from the ground ,what was the total height of the tree?

Answer 1

Answer:

Total height of the tree is 32 m.

Step-by-step explanation:

Imagine one right angled triangled such that its base is 24 m in length(Broken part of the tree touching the ground ) and the length or say the distance of the point from where the tree breaks as the perpendicular length of the triangle.

we need to find the length of the broken part of tree.

By pythagorus theorem

((7)^2 + (24)^2)^1/2 = 25 m.

Hence length of the tree = length of broken part of tree + distance of point (from where the tree breaks ) from the ground

Length of tree = 25m + 7m = 32 m.

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Answer 2

Answer:

Step-by-step explanation:

As the distance of tip is 24 m from the base of the tree and it broke at a height of 7 m.

AB = 7 m

AC = 24 m

In triangle ABC, Applying Pythagoras theorem

$BC^{2} =AB^{2} +AC^{2}$

$BC^2 = 7^2+24^2 \\ BC^2 = 49 + 576\\BC^2 = 625$

$BC=25$,

Total height of tree = AB+BC=7+25=32 m