Question

A tree broke from a point but did not separate. Its top touched the ground at a distance of 24 m from its base. If the point where it broke is at the height of 7 m from the ground, what is the total height of the tree?​

Answer 1

Question:

• Above is the question...

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To prove:

• The total height of tree..

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Formula :- ( Hypoteneous² ) = ( Base² ) + ( Perpendicular² )

⇒( Hypoteneous² ) = ( 24² ) + ( 7² )

⇒ ( Hypoteneous² ) = 576 + 49

⇒ ( Hypoteneous² ) = 625

⇒ Hypoteneous = √625

⇒Hypoteneous = 25

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The total height of tree = 25+ 7 = 32 m

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hope you have got your answer !!

Answer 2

Question :-

A tree broke from a point but did not separate. Its top touched the ground at a distance of 24 m from its base. If the point where it broke is at the height of 7 m from the ground, what is the total height of the tree?

Answer :-

Total height of tree = 25+ 7 = 32 m .

Given :-

The tree top touched the ground at a distance of 24 m from its base. If the point where it broke is at the height of 7 m from the ground.

Have to find :-

What is the total height of the tree?

Solution :-

Now , In ∆ ABC

Simply applying the Pythagoras Theorem :-

↠ ( Hypotense ) ² = ( Perpendicular ) ² + ( Base ) ²

↠( Hypoteneous² ) = ( 24² ) + ( 7² )

↠ ( Hypoteneous² ) = 576 + 49

↠ ( Hypoteneous² ) = 625

↠ Hypoteneous = √625

↠ Hypoteneous = 25

Now the part which touched the ground where it broke is at the height of 7 m from the ground will also be added to the total height of the tree.

• The total height of tree

= 25+ 7

= 32 m