Question

A tree broken at a height of 5m from the ground and its top touches the ground at a distance of 12m from the base of the tree. Find the original height of the tree?

Answer 1

Answer:

total height of the tree

AB+BC

ACB is a right triangle

using Pythagoras theorem

(BC) ^=(AC) ^+(AB) ^

(BC) ^=(5m) ^ +(12m) ^

(BC) ^=25m^+144m^

(BC) ^=169m^

BC=√169m^

BC=13×13m

BC=13m

therefore the height of the tree=5m+13m=18m

Answer 2

Answer:

• Original height of tree is 18 m

Step-by-step explanation:

Given:

• A tree is broken at a height of 12 m from the ground
• Its top touches the ground at a distance of 9 m from the base of the tree.

To Find:

• Original height of tree

Solution:

Let ∆ABC be the right traingle, right angles at B .

Since tree is vertical

• ∠B = 90°

AB = 5 m

BC = 12 m

Using, Phytgeores Theorem,

➠ (AC)² = (AB)² + (BC)²

➠ (AC)² = (12)² + (5)²

➠ (AC)² = 144 + 25

➠ (AC)² = 169

➠ AC = 13 m

Original height of tree = AB + AC

Original height of tree = 5 + 13 = 18 m

Hence,

• Original height of tree is 18 m

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