a tree broken at a height of 5m from the ground.Its top touches the ground at the distance of 12m from the base of the tree find the original height of the tree.
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Given:
- A tree broken at a height of 5m from the ground.
- Its top touches the ground at the distance of 12m from the base of the tree
To Find:
- Find the original height of the tree.
Solution:
Let ∆ABC be the right triangle
The tree is vertical So ∠B = 90°
- AB = 5 cm
- BC = 12 cm
Using Pythagoras theorem,
→ (AC)² = (AB)² + (BC)²
→ (AC) = (5)² + (12)²
→ (AC)² = 25 + 144
→ (AC)² = 169
→ AC = √169
→ AC = 13 cm
Original height = AB + AC
Original height = 5 + 13 = 18 cm
Hence,
- The original height of the tree is 18 cm
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