A tree broken at a point but didn't seperate . Its top touchedthe ground at a distance of 8 m away from its base . If the broke at a height of 6 m above the groud . what was the total height of tree before it broke ?
Answers
Answer:
Step-by-step explanation:
Form a right-angled triangle ABC, right-angled at B. Mark A at the top vertex. Extend line AB. Mark the extended line as D. Name the base vertex as C.
So we get to know that line AB is the height of the unbroken tree, So it is of 2.5dm.
The broken part of the tree is 6dm away from its base.That is the length of line BC.
And line BD is the original length of the tree.
AD is the length of the broken tree.
Time for the solution!
By pythagoras theorem,
AD²= AB²+BC²
AD²= (2.5)²+ (6)²
AD²= 6.25+36
AD²= 42.25
AD²= (6.25)²
AD²= 6.25 dm
Therefore, the original length of the tree is AD+AB. That is equal to 6.25+2.5= 8.75dm.
Therefore, the original length of the tree is 8.75dm.
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