Question

A tree broken due to storm at a point but did not get separate. its top touched the ground at a distance of 10m from its base. If the height of the point from the ground, at which the tree was broken is 0.48 of the total height of the tree. Find its height

Answer 1

Answer:

broken part of the tree which touches the groung is like a hypotenuse of a right angled triangle.

Step-by-step explanation:

and we know that

${h}^{2} = {p}^{2} + {b}^{2}$

where p=0.48m and b =10m and h=?

${h}^{2} = {p}^{2} + {b}^{2} \\ \: \: \: \: \: \: = {(0.48)}^{2} + {10}^{2} \\ \: \: \: \: \:$

solve this equation and find the value of h

After you get the value of h, add the value of h and 0.48.

you will get your answer