Question

A tree casts a 25-foot shadow on a sunny day, as shown in the diagram below. If the angle of elevation from the tip of the shadow to the top of the tree is 32°, what is the height of the tree to the nearest foot?

Answer 1

Answer:

15.62

Step-by-step explanation:

Answer 2

Answer:

The height of the tree is 15.6ft

Step-by-step explanation:

Given that,

A tree casts a 25-foot shadow on a sunny day, as shown in the diagram below and the angle of elevation from the tip of the shadow to the top of the tree is 32° we are required to find the height of he tree.We shall use trigonometry to solve this problem.

Let the height of the tree be h

Length of the shadow is l=25ft

From the figure shown above we have sn trigonometric ratio,

$tan32°=\frac{h}{l} \\ = > h = l \tan(32 {}^{0} )$

Substituting the value of length in above relation,we get

$h = 25 \times 0.624 = 15.6ft$

Therefore,the height of the tree is 15.6ft

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